3.18 \(\int (c \cos (a+b x))^{5/2} \, dx\)

Optimal. Leaf size=70 \[ \frac {6 c^2 E\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {c \cos (a+b x)}}{5 b \sqrt {\cos (a+b x)}}+\frac {2 c \sin (a+b x) (c \cos (a+b x))^{3/2}}{5 b} \]

[Out]

2/5*c*(c*cos(b*x+a))^(3/2)*sin(b*x+a)/b+6/5*c^2*(cos(1/2*b*x+1/2*a)^2)^(1/2)/cos(1/2*b*x+1/2*a)*EllipticE(sin(
1/2*b*x+1/2*a),2^(1/2))*(c*cos(b*x+a))^(1/2)/b/cos(b*x+a)^(1/2)

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Rubi [A]  time = 0.04, antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2635, 2640, 2639} \[ \frac {6 c^2 E\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {c \cos (a+b x)}}{5 b \sqrt {\cos (a+b x)}}+\frac {2 c \sin (a+b x) (c \cos (a+b x))^{3/2}}{5 b} \]

Antiderivative was successfully verified.

[In]

Int[(c*Cos[a + b*x])^(5/2),x]

[Out]

(6*c^2*Sqrt[c*Cos[a + b*x]]*EllipticE[(a + b*x)/2, 2])/(5*b*Sqrt[Cos[a + b*x]]) + (2*c*(c*Cos[a + b*x])^(3/2)*
Sin[a + b*x])/(5*b)

Rule 2635

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> -Simp[(b*Cos[c + d*x]*(b*Sin[c + d*x])^(n - 1))/(d*n),
x] + Dist[(b^2*(n - 1))/n, Int[(b*Sin[c + d*x])^(n - 2), x], x] /; FreeQ[{b, c, d}, x] && GtQ[n, 1] && Integer
Q[2*n]

Rule 2639

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticE[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ[{
c, d}, x]

Rule 2640

Int[Sqrt[(b_)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[b*Sin[c + d*x]]/Sqrt[Sin[c + d*x]], Int[Sqrt[Si
n[c + d*x]], x], x] /; FreeQ[{b, c, d}, x]

Rubi steps

\begin {align*} \int (c \cos (a+b x))^{5/2} \, dx &=\frac {2 c (c \cos (a+b x))^{3/2} \sin (a+b x)}{5 b}+\frac {1}{5} \left (3 c^2\right ) \int \sqrt {c \cos (a+b x)} \, dx\\ &=\frac {2 c (c \cos (a+b x))^{3/2} \sin (a+b x)}{5 b}+\frac {\left (3 c^2 \sqrt {c \cos (a+b x)}\right ) \int \sqrt {\cos (a+b x)} \, dx}{5 \sqrt {\cos (a+b x)}}\\ &=\frac {6 c^2 \sqrt {c \cos (a+b x)} E\left (\left .\frac {1}{2} (a+b x)\right |2\right )}{5 b \sqrt {\cos (a+b x)}}+\frac {2 c (c \cos (a+b x))^{3/2} \sin (a+b x)}{5 b}\\ \end {align*}

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Mathematica [A]  time = 0.08, size = 62, normalized size = 0.89 \[ \frac {(c \cos (a+b x))^{5/2} \left (6 E\left (\left .\frac {1}{2} (a+b x)\right |2\right )+\sin (2 (a+b x)) \sqrt {\cos (a+b x)}\right )}{5 b \cos ^{\frac {5}{2}}(a+b x)} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*Cos[a + b*x])^(5/2),x]

[Out]

((c*Cos[a + b*x])^(5/2)*(6*EllipticE[(a + b*x)/2, 2] + Sqrt[Cos[a + b*x]]*Sin[2*(a + b*x)]))/(5*b*Cos[a + b*x]
^(5/2))

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fricas [F]  time = 0.42, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\sqrt {c \cos \left (b x + a\right )} c^{2} \cos \left (b x + a\right )^{2}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*cos(b*x+a))^(5/2),x, algorithm="fricas")

[Out]

integral(sqrt(c*cos(b*x + a))*c^2*cos(b*x + a)^2, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (c \cos \left (b x + a\right )\right )^{\frac {5}{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*cos(b*x+a))^(5/2),x, algorithm="giac")

[Out]

integrate((c*cos(b*x + a))^(5/2), x)

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maple [B]  time = 0.07, size = 213, normalized size = 3.04 \[ -\frac {2 \sqrt {c \left (2 \left (\cos ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1\right ) \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}\, c^{3} \left (-8 \cos \left (\frac {b x}{2}+\frac {a}{2}\right ) \left (\sin ^{6}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )+8 \left (\sin ^{4}\left (\frac {b x}{2}+\frac {a}{2}\right )\right ) \cos \left (\frac {b x}{2}+\frac {a}{2}\right )-3 \sqrt {\frac {1}{2}-\frac {\cos \left (b x +a \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1}\, \EllipticE \left (\cos \left (\frac {b x}{2}+\frac {a}{2}\right ), \sqrt {2}\right )-2 \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right ) \cos \left (\frac {b x}{2}+\frac {a}{2}\right )\right )}{5 \sqrt {-c \left (2 \left (\sin ^{4}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-\left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )\right )}\, \sin \left (\frac {b x}{2}+\frac {a}{2}\right ) \sqrt {c \left (2 \left (\cos ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1\right )}\, b} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*cos(b*x+a))^(5/2),x)

[Out]

-2/5*(c*(2*cos(1/2*b*x+1/2*a)^2-1)*sin(1/2*b*x+1/2*a)^2)^(1/2)*c^3*(-8*cos(1/2*b*x+1/2*a)*sin(1/2*b*x+1/2*a)^6
+8*sin(1/2*b*x+1/2*a)^4*cos(1/2*b*x+1/2*a)-3*(sin(1/2*b*x+1/2*a)^2)^(1/2)*(2*sin(1/2*b*x+1/2*a)^2-1)^(1/2)*Ell
ipticE(cos(1/2*b*x+1/2*a),2^(1/2))-2*sin(1/2*b*x+1/2*a)^2*cos(1/2*b*x+1/2*a))/(-c*(2*sin(1/2*b*x+1/2*a)^4-sin(
1/2*b*x+1/2*a)^2))^(1/2)/sin(1/2*b*x+1/2*a)/(c*(2*cos(1/2*b*x+1/2*a)^2-1))^(1/2)/b

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (c \cos \left (b x + a\right )\right )^{\frac {5}{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*cos(b*x+a))^(5/2),x, algorithm="maxima")

[Out]

integrate((c*cos(b*x + a))^(5/2), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int {\left (c\,\cos \left (a+b\,x\right )\right )}^{5/2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*cos(a + b*x))^(5/2),x)

[Out]

int((c*cos(a + b*x))^(5/2), x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*cos(b*x+a))**(5/2),x)

[Out]

Timed out

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